IndexOf problem

Find out why the . goes before the /

Moderator: Paul Tuersley

Post Reply
ghaith
Posts: 13
Joined: October 23rd, 2009, 2:45 am

November 2nd, 2009, 12:20 pm

hi all
i know i have many questions but for now the most important is how to use String.indexOf()

i don't know why it is not working for me any idea .


thank you :shock:
User avatar
lloydalvarez
Enhancement master
Posts: 460
Joined: June 17th, 2004, 9:27 am
Location: New York City, NY
Contact:

November 2nd, 2009, 1:35 pm

Code: Select all

var str = "my string";

str.indexOf("m");    //result:  0
str.indexOf("s");    //result:  3
str.indexOf("t");    //result:  4
laracroft
Posts: 3
Joined: November 10th, 2009, 12:22 pm

November 16th, 2009, 5:24 am

Hi Ghaith. I am Lara.

Lloydalvarez's code is working. You should try this.

Have a nice day.
User avatar
luigihmtz
Posts: 5
Joined: July 10th, 2013, 5:56 pm
Location: Mexico City
Contact:

May 4th, 2014, 1:49 am

Hello, everyone.

It turns out that the indexOf method works fine with strings, but it fails when used with arrays, as opposed to regular javascript, which supports either.

For instance, this expression would cause an error in AE, as it shows Undefined because the variable contains an array. If you try this e.g. on "web" javascript, it won't break:

Code: Select all

fruits = ["Banana", "Orange", "Apple", "Mango"];
a = fruits.indexOf("Apple"); 
But this one will always work because the variable contains a string, not an array:

Code: Select all

numbers = "95? 10, 034";
a = numbers.indexOf("5"); 
So how can I retrieve an index number from some whole element (not an individual character) that is part of an array of strings by typing its full string? Just like my fruits example above.

BTW I'm using AECC. Cheers.
Last edited by luigihmtz on May 5th, 2014, 3:22 pm, edited 3 times in total.
User avatar
lloydalvarez
Enhancement master
Posts: 460
Joined: June 17th, 2004, 9:27 am
Location: New York City, NY
Contact:

May 4th, 2014, 8:18 am

luigihmtz wrote: It turns out that the indexOf method works fine with strings, but it fails when used with arrays, as opposed to regular javascript, which supports either.
IndexOf is a string function and doesn't work with arrays anywhere. To get an item in an array by index you simply do this:

Code: Select all

myArray[3]; //gets the third item in the array
http://www.w3schools.com/js/js_obj_array.asp
User avatar
luigihmtz
Posts: 5
Joined: July 10th, 2013, 5:56 pm
Location: Mexico City
Contact:

May 5th, 2014, 1:35 pm


IndexOf is a string function and doesn't work with arrays anywhere.
Sorry, my bad, I mixed up stuff.

I do know that indexOf has a string-only input parameter but, at least in regular javascript, it is NOT a string-only method. What I mean is that you can use either an array of strings or a mere string interchangeably along with indexOf.

That said, my setback remains true: After Effects appears to be capable of handling strings only, not arrays, regarding the thing whom indexOf is applied to. I also acknowledge that you can call any element by its index, but I need to do the opposite (hence the use of the indexOf), I mean, by bringing in a given string element I'll get its corresponding index number, which is the output i need.

I'm still trying to figure this out, but thanks for such a quick answer. :o
User avatar
luigihmtz
Posts: 5
Joined: July 10th, 2013, 5:56 pm
Location: Mexico City
Contact:

May 5th, 2014, 1:37 pm

luigihmtz wrote:

IndexOf is a string function and doesn't work with arrays anywhere.
Sorry, my bad, I mixed up stuff.

I do know that indexOf has a string-only input parameter but, at least in regular javascript, it is NOT a string-only method. What I mean is that you can use either an array of strings or a mere string interchangeably along with indexOf.

That said, my setback remains true: After Effects appears to be capable of handling strings only, not arrays, regarding the thing whom indexOf is applied to. I also acknowledge that you can call any element by its index, but I want to do the opposite (hence the use of the indexOf), I mean, by bringing in a given string element I'll get its corresponding index number, which is the output i need.

I'm still trying to figure this out, but thanks for such a quick answer. :o
User avatar
lloydalvarez
Enhancement master
Posts: 460
Joined: June 17th, 2004, 9:27 am
Location: New York City, NY
Contact:

May 5th, 2014, 2:44 pm

After Effects scripting is "regular" javascript. They are only different in the extended methods. All the base Javascript is exactly the same, i think you are misunderstanding strings and arrays.
User avatar
luigihmtz
Posts: 5
Joined: July 10th, 2013, 5:56 pm
Location: Mexico City
Contact:

May 5th, 2014, 3:15 pm

Hopefully this should make my point clearer:
For instance, this expression would cause an error in AE, as it shows Undefined because the variable contains an array. If you try this e.g. on "web" javascript, it won't break:

Code: Select all

fruits = ["Banana", "Orange", "Apple", "Mango"];
a = fruits.indexOf("Apple"); 
But this one will always work because the variable contains a string, not an array:

Code: Select all

numbers = "95? 10, 034";
a = numbers.indexOf("5"); 
Thanks!
User avatar
luigihmtz
Posts: 5
Joined: July 10th, 2013, 5:56 pm
Location: Mexico City
Contact:

May 5th, 2014, 4:12 pm

OK, I came out with this:

Code: Select all

feed = "Banana";
fruits = [ ];
fruits[0] = "Banana";
fruits[1] = "Orange";
fruits[2] = "Apple";
fruits[3] = "Mango";

for (var i=0; i<fruits.length; i++)
  {
	if ( feed == fruits[i] ){
	  idx = i;
	  break;
	} else { 0 }
}
Not quite elegant, but it works.
beginUndoGroup
Posts: 80
Joined: November 27th, 2012, 6:41 am

May 6th, 2014, 2:06 pm

ExtendScript implements ECMA Standard 262 3rd Edition (December 1999), while the latest 'official' edition is the 5th (June 2011).
There are now plenty of new methods for arrays, like indexOf, every, forEach, map, filter, reduce, some...
But ExtendScript doesnt have them.

You can do something like this:

Code: Select all

function myIndexOf(array, x){
	var n=-1, N=array.length;
	while (++n<N && array[n]!==x);
	return n<N ? n : -1;
	};
Post Reply